Two sound waves with wavelengths 5.0 cm and 5.5 cm, respectively each propagate in a gas with velocity 330 m/s. The number of beats per second will be …………

Two sound waves with wavelengths 5.0 cm and 5.5 cm, respectively each

1.	Two sound waves with wavelengths 5.0 cm and 5.5 cm, respectively each propagate in a gas with velocity 330 m/s. The number of beats per second will be …………
Answer» 0 1 6 12 Solution :NUMBER of beats/s is= `330 [(1)/(5) - (1)/(5.5)] = 6`