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Two solid spheres of same metal but of mass M and 8M fall simultaneously on a viscous liquid and their terminal velocitied are v and n v, then value of n isA. 16B. 8C. 4D. 2 |
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Answer» Correct Answer - C The terminal velocity is given by v, where `v prop r^(2)` (r=radius of the sphere). The mass of the sphere can be given by `m=(4)/(3)pi r^(3)rho`. Thus `m prop r^(3)` So, according to the question, `(m_(1))/(m_(2))=(1)/(8)=((r_(1))/(r_(2)))^(2) implies (r_(1))/(r_(2))=(1)/(2)` and since, `(v_(1))/(v_(2))=((r_(1))/(r_(2)))^(2)=((1)/(2))^(2)=(1)/(4)=(v)/(nv)=(1)/(4) implies n=4` |
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