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Two solenoids `A` and `B` spaced close to each other and sharing the same cylindrical axis have `400` and `700` turns, respectively. A current of `3.50A` in coil `A` produced an average flux of `300muT-m^2` through each turn of `A` and `a` flux of `90.0mT-m^2` through each turn of `B`. a. Calculate the mutual inductance of the two solenoids. b.What is the self inductance of `A`? c. What emf is induced in `B` when the current in `A` increases at the rate of `0.5A//s`? |
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Answer» Here, `M = ? dI = 6 - 2 = 4 A, dt = 0.1 s, e = 1 V` From `e = M dI//dt` `M = (e. dt)/(dI) = (1 xx 0.1)/(4) = 0.025 H` |
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