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Two small spheres each of mass 'm' kg and having equal charge are suspended from a point by insulating threads each of length 'I' metre but negligible mass. If '0' is the angle which each string makes with vertical when equilibrium has been reached, find charge on one sphere. |
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Answer» T cos θ = mg T sin θ = Fe tan θ = \(\frac{Fe}{mg}\) \(Fe = \frac{kq^2}{r^2}\) \(Fe = \frac{kq^2}{(2d)^2}\) \(Fe = \frac{kq^2}{4l^2 sin^2\theta}\) \(tan\theta= \frac{kq^2}{4l^2sin^{2} \theta\times mg}\) \(q^2 = (4mgl^2\,sin^2\theta\, tan\theta)4\pi\varepsilon\) |
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