1.

Two simple harmonic motions act on a particle. These harmonic motions are x=Acos(omegat+delta),y=Acos(omegat+alpha) When delta=alpha+(pi)/(2), the resulting motion is…………..

Answer»

A circle and the actual motion is clockwise
an ELLIPSE and the actual motion is COUNTER clockwise
a ellipse and the actual motion is clockwise
a circle and the actual motion is counter clockwise

Solution :`X=Acos(omegat+alpha+(pi)/(2))=-ASIN(omegat+alpha)`
`y=Acos(omegat+alpha)`
Squaring and ADDING the two equations, We get `x^(2)+y^(2)=A^(2)`. This is an equation of a circle Hence the resultant motion is circular. The motion is counter clockwise.


Discussion

No Comment Found