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Two similar springs P and Q have spring constants K_p and K_Q, such that K_p > K_Q. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs W_P and W_Q are related as, in case (a) and case (b) respecitively |
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Answer» `W_P GT W_Q , W_Q gt W_P` Case (a) : Elongation (X) in each spring is same. `W_P = 1/2 K_px^2 , W_Q = 1/2 K_Q x^2 :. W_P > W_Q` Case (b) : Force of elongation is same. So, `x_1 = F/(K_P) and x_2 = F/(K_Q)` `W_P = 1/2 K_p x_1^2 = 1/2 (F^2)/(K_P) , W_Q = 1/2 K_Q x_2^2 = 1/2 (F^2)/(K_Q)` `:. W_P < W_Q` . |
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