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Two satellite A and B are orbiting around the Earth in circular orbits of the same radius. The mass of A is 16 times that of B. What I sthe ratio of the period of revolution of B to that A ? |
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Answer» Solution :`T = (2 PI r)/(upsilon)` and `upsilon = sqrt(Gm//r)`, where `M` is the mass of the Earth. It means `T` is independent of mass of the satellite but depends upon the RADIUS of the ORBITAL PATH. So `T_(B)//T_(A) = 1: 1` |
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