1.

Two samples X and Y contain equal amount of radioactive substances. If 1^(th)/16 of the sample Y , remain after 8 hours, then the ratio of half life periods of X and Y is

Answer»

`2:1`
`1:2`
`1:4`
`4:1`

Solution :As `N/N_0=(1/2)^n`
where, number of HALF lives , `n=t/T`
T is the half LIFE period
For SAMPLE X
`1/16=(1/2)^(8//T_X)` or `(1/2)^4 =(1/2)^(8//T_X)`
`RARR 4=8/T_X` ….(i)
For sample Y
`(1/256)=(1/2)^(8//T_Y)` or `(1/2)^8=(1/2)^(8//T_Y)`
`8=8/T_Y` ...(II)
Dividing (i) by (ii) , we get
`4/8=8/T_X xx T_Y/8`
`1/2=T_Y/T_X` or `T_X/T_Y=2/1`


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