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Two rods A and B of equal lengths. Each rod has its ends at temperature T1 and T2. What is the condition that will ensure equal rates of flow of heat through the rods A and B? |
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Answer» Since, Q = KA(θ1 − θ2)t/x \(\frac{Q_A}{t}\) = KAAA(θ1 − θ2)/x \(\frac{Q_B}{t}\) = KBAB(θ1 − θ2)/x For quale rates of flow \(\frac{Q_A}{t}\) = \(\frac{Q_B}{t}\) or KAAA = KBAB. |
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