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Two resistors are connected (a) in series (b) in parallel The equivalent resistance in the two cases are `9 ohm` and `2ohm` respectively. Then the resistances of the component resistor areA. `2 ohm` and `7 ohm`B. `3 ohm` and `6 ohm`C. `3 ohm` and `9 ohm`D. `5 ohm` and `4 ohm` |
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Answer» Correct Answer - B (b) `R_(1) + R_(2) = 9` and `(R_(1) R_(2))/(R_(1) + R_(2)) = 2 implies R_(1) R_(2) = 18` `R_(1) - R_(2) = sqrt((R_(1) + R_(2))^(2) - 4 R_(1) R_(2)) = sqrt(81 - 72) = 3` `R_(1) = 6 Omega, R_(2) = 3 Omega` |
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