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Two resistor one of 10 ohm and other 20 ohm are connected in series to a 6 volt battery. The current in the circuit will be

Answer» ERE's the ANSWER Effective RESISTANCE ACROSS the circuit in series= 20Ω + 10Ω =30ΩV=IR6= I*30I= 6÷30 =0.5AHope it HELPED!!


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