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Two resistances R1 and R2 of 2 ohm and 3 ohm respectively are connected in parallel with a 1.5 volt battery and the battery current is found to be 0.75 A.(i) Find the internal resistance of the battery.(ii) Find the power developed across R1. |
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Answer» ONG>Answer: 26. (i) 0.8 ohm
(ii)current through R1 = (3/5) of 0.75 A or, 0.45 A, power = I^2R1 = (0.45)^2 x 2 WATT = 0.4 watt Explanation: Mark me BRAINLIEST |
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