1.

Two resistances R1 and R2 of 2 ohm and 3 ohm respectively are connected in parallel with a 1.5 volt battery and the battery current is found to be 0.75 A.(i) Find the internal resistance of the battery.(ii) Find the power developed across R1.​

Answer» ONG>Answer:

26.

(i) 0.8 ohm

(ii)current through R1 = (3/5) of 0.75 A

or, 0.45 A, power = I^2R1 = (0.45)^2

x 2 WATT = 0.4 watt

Explanation:

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