Saved Bookmarks
| 1. |
Two resistances R1 and R2 of 2 ohm and 3 ohm respectively are connected in parallel with a1.5 volt battery and the battery current is found to be 0.75 A.(i) Find the internal resistance of the battery.(ii) Find the power developed across R1. |
|
Answer» Answer: 26. (i) 0.8 ohm (II)current through R1 = (3/5) of 0.75 A or, 0.45 A, POWER = I^2R1 = (0.45)^2 x 2 WATT = 0.4watt Explanation: Mark me Brainliest |
|