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Two resistances of values 150 pm 2 Omega" and "250 pm 5 Omega are connected in series. Find their equivalent resistance. |
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Answer» Solution :GIVEN, `R_(1)= 150 pm 2 Omega, R_(2)-250 pm 5 Omega` Equivalent resistance `R= R_(1)+R_(2)= (150+250)pm (2+5)` `=(400 pm 7) Omega`. |
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