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Two resistances of R1= 5 omaga and R2 = 10 omaga are connected to a 24V battery. Find a] the effective resistance [b] the current in the section AB [c] theCurrent through each resistance, |
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Answer» re two possibilities in which the resistors can be connected1) Series Net RESISTANCE Rs =R 1+ R 2 Rs =15 ohmVoltage of the BATTERY =25V Current flowing through the combinationI = V /Rs I =25/15I=1.6 ohmwe know that in series COMBINATION the current flowing through both the resistors is the sameI 1= I 2 = 1.6 A2) ParallelR 1 and R2 are connected in parallelNet resistanceRp =R 1×R 2/ R 1+ R 2Rp=25×15/40Rp=9.37 ohmsVoltage of the battery=25 V Current flowing through the parallel combinationI = V /RP =25/9.37I=2.66AIn parallel combination we know that the voltage across both the resistors is the sameI 1 = V /R 1 = 25/25 =1 AI 2 = V / R 2 =25 /15 =1.66 A |
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