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Two resistance `R_(1)` and `R_(2)` are made of different material. The temperature coefficient of the material of `R_(1)` is `alpha` and of the material of `R_(2)` is `-beta`. Then resistance of the series combination of `R_(1)` and `R_(2)` will not change with temperature, if `R_(1)//R_(2)` will not changee with temperature if `R_(1)//R_(2)` equalsA. `(alpha)/(beta)`B. `(alpha + beta)/(alpha - beta)`C. `(alpha^(2) + beta^(2))/(alpha beta)`D. `(beta)/(alpha)` |
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Answer» Correct Answer - D (d) `R_(1) + R_(2) = R_(1) (1 + alpha t) + R_(2) (1 - beta t)` `implies R_(1) + R_(2) = R_(1) + R_(2) + R_(1) alpha r = R_(2) beta t implies (R_(1))/(R_(2)) = (beta)/(alpha)` |
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