Two protons of equal kinetic energies enter a region of uniform magnet

1.	Two protons of equal kinetic energies enter a region of uniform magnetic field. The first proton enters normal to the field direction while the second enters at 30 to the field direction. what will be the change in de broglie wavelength of proton after that?
Answer» $\huge\bold{HEY:)-}$ ⭐⭐⭐⭐⭐⭐ ⭐ ⭐ ⭐ ⭐ ⭐ ❤❤❤⭐⭐⭐⭐ $\\ \\ \\ \\ \\$ ⤵⤵⤵⤵ FOLLOW , BRAINLIST ME☺☺PLZZ =========== We know that when a charged particle enters a UNIFORM magnetic field the force exerted on it, F = Q(v X B) = qvb sin∅ Case I : when the particle enters perpendicular,∅ = 90 In this case since sin∅ = 1 is the maximum value and the direction of the force is perpendicular to the direction of motion of particle, hence the particle starts moving in a CIRCULAR path with radius, r= mv/bq Case II : the particle enters at an ANGLE of 30⁰: In this case the force acting on it has two components, one parallel to the motion which will cause a linear motion, the other component will ACT perpendicular to motion which will cause circular motion. Hence DUE to the resultant of these two component the particle will move along a HELICAL path.

Two protons of equal kinetic energies enter a region of uniform magnetic field. The first proton enters normal to the field direction while the second enters at 30 to the field direction. what will be the change in de broglie wavelength of proton after that?

Answer»

$\huge\bold{HEY:)-}$

⭐⭐⭐⭐⭐⭐ ⭐ ⭐ ⭐ ⭐ ⭐ ❤❤❤⭐⭐⭐⭐ $\\ \\ \\ \\ \\$

⤵⤵⤵⤵

FOLLOW , BRAINLIST ME☺☺PLZZ

===========

We know that when a charged particle enters a UNIFORM magnetic field the force exerted on it,

F = Q(v X B) = qvb sin∅

Case I : when the particle enters perpendicular,∅ = 90

In this case since sin∅ = 1 is the maximum value and the direction of the force is perpendicular to the direction of motion of particle, hence the particle starts moving in a CIRCULAR path with radius,

r= mv/bq

Case II : the particle enters at an ANGLE of 30⁰:

In this case the force acting on it has two components, one parallel to the motion which will cause a linear motion, the other component will ACT perpendicular to motion which will cause circular motion.

Hence DUE to the resultant of these two component the particle will move along a HELICAL path.

Two protons of equal kinetic energies enter a region of uniform magnetic field. The first proton enters normal to the field direction while the second enters at 30 to the field direction. what will be the change in de broglie wavelength of proton after that?

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