Two protons are having same kinetic energy. One proton enters a uniform magnetic field at right angles ot it. Second proton enters a uniform electric field in the direction of field. After some time their de Broglie wavelengths are `lambda_1 and lambda_2` then (a) `lambda_1 = lambda_2` (b) `lambda_1 lt lambda_2` (c) `lambda_1 gt lambda_2` (d) some more information is requiredA. `lambda_(1) = lambda_(2)`B. `lambda gt lambda_(2)`C. `lambda_(2) gt lambda_(1)`D. None of these

Two protons are having same kinetic energy. One proton enters a unifor

1.	Two protons are having same kinetic energy. One proton enters a uniform magnetic field at right angles ot it. Second proton enters a uniform electric field in the direction of field. After some time their de Broglie wavelengths are `lambda_1 and lambda_2` then (a) `lambda_1 = lambda_2` (b) `lambda_1 lt lambda_2` (c) `lambda_1 gt lambda_2` (d) some more information is requiredA. `lambda_(1) = lambda_(2)`B. `lambda gt lambda_(2)`C. `lambda_(2) gt lambda_(1)`D. None of these
Answer» Correct Answer - D We have work is done by only electric field. Thus if `bar(E)\|\|vec(v),\|vec(v)\|` decreases, & thus momentum of electron decreases & vice-versa, while in magnetic field `\|vec(v)\|` remains constant.

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