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two poles of heights 15 m and 24 m stand on a plane ground. If the distance between their feet is 12 m , find the distance between their tops. ​

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ong>Answer:

ANSWER

ANSWERLet RS be POLE of height 10 m and PT be pole of height 15m.

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their FEET i.e. 12m.

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2 =5

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2 =5 2

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2 =5 2 +12

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2 =5 2 +12 2

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2 =5 2 +12 2 =25+144

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2 =5 2 +12 2 =25+144PR=13 m.

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2 =5 2 +12 2 =25+144PR=13 m.Hence, the distance between their tops is 13m.

ANSWERLet RS be pole of height 10 m and PT be pole of height 15m.ST is the distance between their feet i.e. 12m.∴RQ=ST=12 m And, RS=QT=10m ....[∵□RQTS is a rectangle]Now, in △PQR,By Pythagoras theorem,PR 2 =PQ 2 +QR 2 ∴PR 2 =5 2 +12 2 =25+144PR=13 m.Hence, the distance between their tops is 13m.solution

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