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Two point charges q1 = 400 micro coulomb and q2=100 micro coulomb are kept fixed 60 cm apart in vacuum find intensity of the electric field at mid point of the line joining q1 and q2 |
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Answer» q1 = 400 micro coulomb q2=100 micro coulombDistance - 60 CMFIND - Intensity of electric field at mid point of the two charges.Solution - The formula to calculate intensity of electric field is as follows- E = (1/4π€)(Q/r²)In the formula, E refers to electric field, (1/4π€) can be written as 9*10^9, Q refers to charges. R² denotes the point at which Intensity of elctric field is to be calculated. Since the intensity is to be calculated at mid point, the equation will be - E = E1 - E2R will be 30 CM(due to mid point) = 0.3 m.Q1 for E1 - 400 microC = 4*10^-4 CQ2 for E2 - 100 microC = 1*10^-4 CE1 = 9*10^9*4*10^-4/(0.3)²E1 = 4*10^7 NCE2 = 9*10^9*1*10^-4/(0.3)²E2 = 1*10^7 NCTherefore, E = 4*10^7 - 1*10^7E = 3*10^7 NCHence, intensity of electric field at mid point will be 3*10^7 NC. |
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