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Two point charges of +2microcoulomb and +6microcoulomb repel each other with a force of 12n. if each is given as additional charge of -4microcoulomb . what will be the new force​

Answer»

-4NExplanation: You can use the formula, F=Kq1q2/r^2=> 12=9×10^9×2×10^-6×6×10-6/r^2From here we get the value of r^2=9×10^-3Now, after ADDING a charge of 4 micro COULOMB each, new CHARGES becomes -2uC and 2uC, so again using the formula, we get the value of F' = -4N



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