1.

Two point charge of 5×10c and 20×10c are separated by a distance 2m .At which point on line joining them electric field is zero

Answer»

Given q 1 =5×10 −19 C and q 2 =20×10 −19 C with r=2mSuppose at a point x METER away from q_1 the FIELD is zero then at that point the field due to INDIVIDUAL charges should be equal and opposite x 2 q 1 = (2−x) 2 q 2 which lead us to x=2/3 meter from CHARGE 5×10 −19 C



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