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Two pistons of a hydraulic lift have diameters of 120 cm and 5 cm. What is the force exerted by the larger piston when 60 N is placed on the smaller piston?

Answer»

ong>Answer:

The force EXERTED by the larger piston when 50N is placed on the SMALLER piston is 7200 N. Explanation: Given that, TWO pistons of a hydraulic lift having diameters of 60 cm and 5 cm.



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