Two pipes X and Y can fill a container in \(37\frac{1}{2}\) minutes a

1.	Two pipes X and Y can fill a container in \(37\frac{1}{2}\) minutes and 45 minutes respectively. If both the pipes are opened together, then the container will be filled in half an hour. After how much time pipe Y should be turned off?1. 15 minutes2. 10 minutes3. 5 minutes4. 9 minutes
Answer» Correct Answer - Option 4 : 9 minutes Given: Two pipes X and Y can fill a container in \(37\frac{1}{2}\) minutes and 45 minutes respectively Concept: If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank. Calculation: Pipe X fills the container in \(\frac{{75}}{2}\) minutes. Part of the container filled by X in 30 minutes ⇒ (2/75) × 30 ⇒ 4/5 Remaining part = 1 – (4/5) ⇒ 1/5 Now, 1 part is filled by pipe Y in 45 minutes 1/5 part is filled in = 45 × 1/5 ⇒ 9 minutes ∴ The pipe Y should be turned off after 9 minutes.

Two pipes X and Y can fill a container in \(37\frac{1}{2}\) minutes and 45 minutes respectively. If both the pipes are opened together, then the container will be filled in half an hour. After how much time pipe Y should be turned off?1. 15 minutes2. 10 minutes3. 5 minutes4. 9 minutes

Answer» Correct Answer - Option 4 : 9 minutes

Given:

Two pipes X and Y can fill a container in \(37\frac{1}{2}\) minutes and 45 minutes respectively

Concept:

If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.

Calculation:

Pipe X fills the container in \(\frac{{75}}{2}\) minutes.

Part of the container filled by X in 30 minutes

⇒ (2/75) × 30

⇒ 4/5

Remaining part = 1 – (4/5)

⇒ 1/5

Now, 1 part is filled by pipe Y in 45 minutes

1/5 part is filled in = 45 × 1/5

⇒ 9 minutes

∴ The pipe Y should be turned off after 9 minutes.

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