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Two pipes running together can 6ll a tank in 6minutes. If one pipe takes 5 minutes more than theother to fill the tank, find the time in which eachpipe would fill the tank separately. |
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Answer» Step-by-step explanation: Let the volume of cistern = V litre (L) let the flow RATE of one PIPE be x L/min and that of other pipe be y L/min Since 6 minute are needed to fill the pipe 6x+6y = V = total volume (1) V/x = TIME TAKEN by one pipe and V/y = time taken by other pipe V/x + V/y = 5 min 1/x - 1/y = 5/V (2) Solve Time taken by one pipe = 15 min and Time taken by other pipe = 10 min Option 6) 15 min and 10 min |
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