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Two pipes A and B can fill a tank in 10 hours and 12 hours respectively. Another pipe C can empty the tank in 6 hours. Find the total time taken to fill the tank if all the three pipes are opened at the same time.1. 652. 553. 504. 60 |
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Answer» Correct Answer - Option 4 : 60 Given: Time taken by pipe A to fill the tank = 10 hours Time taken by pipe B to fill the tank = 12 hours Time taken by pipe C to empty the tank = 6 hours Formula used: Total capacity = LCM Efficiency = Total Capacity/Time Concept used: Efficiency of outlet pipe is always in negative Calculation: Total capacity = LCM(10, 12, 6) = 60 Efficiency of pipe A = 60/10 = 6 units Efficiency of pipe B = 60/12 = 5 units Efficiency of pipe C = 60/6 = -10 units Now when all pipes are opened then total efficiency of all the pipes = 11 – 10 = 1 Required time = 60/1 = 60 hours ∴ The total time taken to fill the tank if all the three pipes are opened at the same time is 60 hours |
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