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Two pipes A and B can fill a 1 / 4th filled cistern in 15 and 20 minutes respectively while pipe C can empty that exact 1 / 4th filled cistern in 10 minutes. Find the time required to fill the cistern if all three pipes are open when the cistern itself is empty.1. 20 minutes2. 16 minutes3. 18 minutes4. 24 minutes5. 12 minutes |
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Answer» Correct Answer - Option 2 : 16 minutes Given: Pipe A and B can fill (1-1 / 4) = 3 / 4th of the cistern in 15 and 20 minutes respectively. Pipe C can empty 1 / 4th of the cistern in 10 minutes. Formula used: Total volume = time × rate of resultant water inlet Calculations: Let us assume the total volume of the cistern = 4 × LCM of (15, 20, 10) = 240 lit. A and B can fill 3 / 4th i.e. (240 × 3 / 4) = 180 lit. in 15 and 20 minutes respectively. C can empty 1 / 4th i.e. (240 × 1 / 4) = 60 lit in 10 minutes. Inlet capacity for A = 180 / 15 = 12 lit / min Inlet capacity for B = 180 / 20 = 9 lit / min Outlet capacity for C = 60 / 10 = 6 lit / min If three pipes are open at the same time, rate of resultant inlet = (12 + 9 - 6) = 15 lit / min Time required to fill the completely empty cistern = 240 / 15 = 16 min |
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