Two people push a car for 3 sec, with a combined net force of 200 N.a)

1.	Two people push a car for 3 sec, with a combined net force of 200 N.a) Calculate the impulse provided to the car.b) If the car has a mass of 1200 kg, what will be its change in velocity?
Answer» a) F_net = 200 N ; ∆t =3 sec Impulse ∆p = F_net . ∆t = 200 × 3 = 600 N – sec. b) Mass of the car (m) = 1200 kg.; Net force (F_net ) = 200 N Time ∆t = 3 sec. ; Change in velocity ∆v =? F_net= m. \(\frac{\Delta v}{\Delta t}\) 200 = 1200 \(\times\,\frac{\Delta v}{3}\) ∆v = \(\frac{200}{400}= 0.5\,m/sec.\)

Two people push a car for 3 sec, with a combined net force of 200 N.a) Calculate the impulse provided to the car.b) If the car has a mass of 1200 kg, what will be its change in velocity?

Answer»

a) F_net = 200 N ; ∆t =3 sec

Impulse ∆p = F_net . ∆t = 200 × 3 = 600 N – sec.

b) Mass of the car (m) = 1200 kg.; Net force (F_net ) = 200 N

Time ∆t = 3 sec. ; Change in velocity ∆v =?

F_net= m. \(\frac{\Delta v}{\Delta t}\)

200 = 1200 \(\times\,\frac{\Delta v}{3}\)

∆v = \(\frac{200}{400}= 0.5\,m/sec.\)