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two particles of masses m and 2m have equal kinetic energies .their de-Broglie wavelengths are in the ratio is... |
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Answer» ONG>ANSWER: As we know, λ=h/mv λ= 2mE
h
as the kinetic energy of both PARTICLES are same so λ∝ m
1
λ 2
λ 1
= 1 2
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