Two particles of masses m_1 and m_2in projectile motion have velocities vecv_1 and vecv_2respectively at time t = 0. They collide at time t_0 . Their velocities become vecv_1^2 and vecv_2^1at time 2t_0while still moving in air. The value of |(m_1 vecv_1^1 + m_2vec_2^1) - (m_1vecv_1 + m_2vecv_2)|is

Two particles of masses m_1 and m_2in projectile motion have velocitie

1.	Two particles of masses m_1 and m_2in projectile motion have velocities vecv_1 and vecv_2respectively at time t = 0. They collide at time t_0 . Their velocities become vecv_1^2 and vecv_2^1at time 2t_0while still moving in air. The value of \|(m_1 vecv_1^1 + m_2vec_2^1) - (m_1vecv_1 + m_2vecv_2)\|is
Answer» ZERO `(m_1+m_2) "GT"_0` `2(m_1+m_2)"gt"_0` `1/2 (m_1 + m_2) "gt"_0` ANSWER :C