Two particles of masses 2 kg and 4 kg are approaching towards each other with ccelerations 1m//s^(2) and 2m//s^(2), respectively, on a smooth horizontal suface. Then find the acceleration of centre of mass of the system and direction of acceleration of CM.

Two particles of masses 2 kg and 4 kg are approaching towards each oth

1.	Two particles of masses 2 kg and 4 kg are approaching towards each other with ccelerations 1m//s^(2) and 2m//s^(2), respectively, on a smooth horizontal suface. Then find the acceleration of centre of mass of the system and direction of acceleration of CM.
Answer» SOLUTION :The acceleration of CM of the SYSTEM is given by `a_(CM)=(m_(1)a_(1)+m_(2)a_(2))/(m_(2)+m_(2))impliesa_(CM)=(2xx1+4(-2))/(2+4)=-1m//s^(2)` Negative sign indicates that aceleratioin of CM will be in the direction of acceleration of `4 kg` mass.