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Two particles of equal mass have velocitiesvecV _(1)= 4hati ms^(-1) and vecV _(2)= 4hatj ms^(-1) First particle has an acceleration veca_(1)=(5hati+5hathatj)ms^(-1)while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of |
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Answer» STRAIGHT LINE |
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