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Two particles have the same de Broglie wavelength and one is moving four times as fast as the other. If the slower particle is an α-particle, what are the possibilities for the other particle? |
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Answer» Data : λ1 = λ2 , v1 = 4v2 λ = \(\cfrac{h}p\) = \(\cfrac{h}{mv}\) ∴ λ1 = \(\cfrac{h}{m_1v_1}\), λ2 = \(\cfrac{h}{m_2v_2}\) ∴ m1 = m2 \(\cfrac{v_2}{v_1}\) = m2 \((\cfrac{1}4)\) = \(\cfrac{m_2}4\) As particle 2 is the a-particle, particle 1 (having the mass \(\cfrac{1}4\) times that of the a-particle) may be a proton or neutron. |
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