Two particles are in SHM with same angular frequency and with amplitudes of A and 2A respectively along same straight line with same mean position. They cross each other at position A/2 distance from mean position in opposite direction. The phase difference between them is (If sin−1(1/4)=14.48o)

Two particles are in SHM with same angular frequency and with amplitud

1.	Two particles are in SHM with same angular frequency and with amplitudes of A and 2A respectively along same straight line with same mean position. They cross each other at position A/2 distance from mean position in opposite direction. The phase difference between them is (If sin−1(1/4)=14.48o)
Answer» Two particles are in SHM with same angular frequency and with amplitudes of $A$ and $2 A$ respectively along same straight line with same mean position. They cross each other at position A/2 distance from mean position in opposite direction. The phase difference between them is (If $s i n^{- 1} (1 / 4) = {14.48}^{o}$ )

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Two particles are in SHM with same angular frequency and with amplitudes of A and 2A respectively along same straight line with same mean position. They cross each other at position A/2 distance from mean position in opposite direction. The phase difference between them is (If sin−1(1/4)=14.48o)

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