Two particles are executing SHM in a straightline. Amplitude A and time period T of both the particles are equal. At time t=0, one particle is at displacement x_(1)=+A and the other at x_(2)=(-A)/23 and they are approaching towards each other. After what time they cross each other?

Two particles are executing SHM in a straightline. Amplitude A and tim

1.	Two particles are executing SHM in a straightline. Amplitude A and time period T of both the particles are equal. At time t=0, one particle is at displacement x_(1)=+A and the other at x_(2)=(-A)/23 and they are approaching towards each other. After what time they cross each other?
Answer» Solution :Equation can be written as : `x_(1)=Acos omega t` and `x_(2)=ASIN(omegat-pi//6)"" "Here" omega=(2PI)/T` Equating `x_(1)=x_(2)""Sinx(omegat-(pi)/6)=COS omegat` `SINOMEGAT"cos"(pi)/6-"sin"(pi)/6cosomegast=cos omegat` `tan omega t=sqrt(3), omegat=(2pi)/T t=(pi)/3`, we get `t=T//6`