ite ⭐⭐✨✨^_^:-(:-(:-(:-(:-(:-(:-(:-(Your answer :-):-):-):-):-):-):-):-):-)::-):-)$$$${{{{{{{{{{. Two particles are executing SHM with the same amplitude and frequency, but with a phase difference, and the maximum separation found is equal to amplitude. What is the phase difference?Still have a question? Ask your own!What is your question?4 ANSWERSAnurodh Kumar, B Sc Physics (2011)UPDATED Jan 15, 2019 · Author has 123answers and 45.1k answer viewsLet the first particle be at mean position at t = 0.Equation of shm is GIVEN byx1=Asin(ωt)x1=Asin⁡(ωt)And for second particle equation can be written asx2=Asin(ωt+θ)x2=Asin⁡(ωt+θ)Distance between them|x2−x1||x2−x1|=|A(SIN(ωt)−sin(ωt+θ))|=|A(sin⁡(ωt)−sin⁡(ωt+θ))|=|2Acosωt+ωt+θ2sinθ2|=|2Acos⁡ωt+ωt+θ2sin⁡θ2|=|2Asinθ2cos2×ωt+θ2|=|2Asin⁡θ2cos⁡2×ωt+θ2|From here we find that the lenght x2−x1x2−x1 is oscillating in nature and the maximum value is given by the constant part IE 2Asinθ22Asin⁡θ2 which is eqal to A. From this we can find θθ2Asinθ2=A2Asin⁡θ2=A⟹θ=π3⟹θ=π3So phase difference is π3 }}}}}}}$$$$$$$$£££££&&&&&&&&&&+££Hope Help your ££££££&&&&&&&&&+£££???((((@@((☝️☝️☝️please brainliest this answer☝️☝️))))))??????????????????☘️??????????☝️✨?????????????????????????????????????????☝️^_^✨☝️???????????????????