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Two parallel sides of a trapezium are 60 m and 77 m and the other sides are 25 m and 26 m find the area |
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Answer» ANSWER Draw a perpendicular line BE on DF ABCD is a parallelogram. BC=AD=25 cm CD=AB=60 cm CF=77−CD=17cm For ΔBCF semiperimeter of triangle=225+26+17
=268=34 By Heron's Formula of triangle=s(s−a)(s−b)(s−c) =34(34−25)(34−26)(34−17) =204cm² Also, area of ΔBCF=21×base×height 204=21BE×CF 204=21BE×17 BE=408/17 BE=24 cm Area of Trapezium=21(AB+DF)×BE =1/2(60+77)×24 Area=1644cm²
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