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Two parallel side of a trapezium are 60 cm and 77 cm and other sides are 25 cm and26cm. Find the area of the trapezium. |
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Answer» Answer: Step-by-step explanation: → Draw a line BC PARALLEL to AD → Draw a perpendicular line BE on DF → ABCD is a parallelogram. → BC=AD=25cm → CD=AB=60cm → CF=77-CD=17cm → For Δ BCF ⇒ perimeter of TRIANGLE=(25+26+17)/2 =68/2=34 ⇒ By HERON's Formula of triangle=√s(s-a)(s-b)(s-c) =√34(34-25)(34-26)(34-17) =204cm² ⇒ Now area of ΔBCF=1/2xbase X height =1/2 BExCF204cm² =1/2x BEx17BE =408/17 =24cm ⇒ Area of Trapezium =1/2(AB+DF)xBE =1/2(60+77)x24 =1644cm² |
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