two parallel plates separated by a distance of 1cm have a potential difference of 20Vb/w them the plates are held at the horizontal position with negative plate above the positive plate an electron is released from rest in the upper plate what is the acceleration of the electron

two parallel plates separated by a distance of 1cm have a potential di

1.	two parallel plates separated by a distance of 1cm have a potential difference of 20Vb/w them the plates are held at the horizontal position with negative plate above the positive plate an electron is released from rest in the upper plate what is the acceleration of the electron
Answer» hat,Potential DIFFERENCE = 20 VDistance = 1 cmWe NEED to calculate the ACCELERATION of the electronUsing formula of electric fieldWhere, m = mass of electronq = CHARGE of electronV = potentiald = distancePut the value into the formulaHence, The acceleration of the electron is

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two parallel plates separated by a distance of 1cm have a potential difference of 20Vb/w them the plates are held at the horizontal position with negative plate above the positive plate an electron is released from rest in the upper plate what is the acceleration of the electron

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