Two opposite angles of a parallelogram are (3x – 2)o and (50 –

1.	Two opposite angles of a parallelogram are (3x – 2)o and (50 – x)o. Find the measure of each angle of the parallelogram.
Answer» We know that opposite angles of a parallelogram are equal. So, (3x – 2)° = (50 – x)° 3x° – 2° = 50° – x° 3x° + x° = 50° + 2° 4x° = 52° x° = 52°/4 = 13° Measure of opposite angles are, (3x – 2)° = 3×13 – 2 = 37° (50 – x)° = 50 – 13 = 37° We know that Sum of adjacent angles = 180° Other two angles are 180° – 37° = 143° ∴ Measure of each angle is 37°, 143°, 37°, 143°

Two opposite angles of a parallelogram are (3x – 2)o and (50 – x)o. Find the measure of each angle of the parallelogram.

Answer»

We know that opposite angles of a parallelogram are equal.

So, (3x – 2)° = (50 – x)°

3x° – 2° = 50° – x°

3x° + x° = 50° + 2°

4x° = 52°

x° = 52°/4

= 13°

Measure of opposite angles are,

(3x – 2)° = 3×13 – 2 = 37°

(50 – x)° = 50 – 13 = 37°

We know that Sum of adjacent angles = 180°

Other two angles are 180° – 37° = 143°

∴ Measure of each angle is 37°, 143°, 37°, 143°