Two objects of masses 4kg and 3kg are placed along X and T axes respectively at a distance of 1m from the origin. An object of mass 1kg is kept at the origin of the co-ordinatesystem. Calculate the resultant gravitational force attraction on the object at the origin.

Two objects of masses 4kg and 3kg are placed along X and T axes respec

1.	Two objects of masses 4kg and 3kg are placed along X and T axes respectively at a distance of 1m from the origin. An object of mass 1kg is kept at the origin of the co-ordinatesystem. Calculate the resultant gravitational force attraction on the object at the origin.
Answer» Solution :Force due to 4kg mass on 1kg mass at the origin is `F_(1) = (G xx 4 xx 1)/(1^(2)) = 4G` Force due to 3kg mass on 1 kgmass at the origin is `F_(2) = (G xx 3 xx 1)/(1^(2)) = 3G` The resultant force is found by USING parallelo-gram law of vectors `F = SQRT(F_(1)^(2) + F_(2)^(2) + 2F_(1)F_(2) cos theta)` `= sqrt((4G)^(2) + (3G)^(2) + 2(4g)(3G)cos 90^(@))= 5G`