Two objects of masses 100 g and 200 g are moving along the sameline an

1.	Two objects of masses 100 g and 200 g are moving along the sameline and direction with velocities of 2 m/ s and 1 m /s, respectively.They collide and after the collision, the first object moves at a velocityof 1.67 m /s. Determine the velocity of the second object.
Answer» Answer: heyyyy We can SOLVE the GIVEN problem by using the law of conservation of momentum. Given Mass of one of the OBJECTS (m₁) = 100 g = 0.1 kg Mass of the other object (m₂) = 200 g = 0.2 kg Velocity of m₁ after collision (v3) = 1.67 m/s Velocity of m₁ before collision (v₁) = 2 m/s Velocity of m2 before collision (v₂) = 1 m/s Find out Velocity of m2 after collision=V4 Solution According to the law of conservation of momentum: TOTAL momentum before collision = Total momentum after collision Therefore, m₁v₁ + m₂V₂ = ₁V3 + m₂V4 On sustitututing the known and given values we get 2(0.1) +1(0.2) = 1.67(0.1) + v4× (0.2) 0.4 0.167 + 0.2 × V4 V4= 1.165 m/s Answer Hence, the velocity of the second object becomes 1.165 m/s after the collision. i hope it helps mark me as brainliest please

Two objects of masses 100 g and 200 g are moving along the sameline and direction with velocities of 2 m/ s and 1 m /s, respectively.They collide and after the collision, the first object moves at a velocityof 1.67 m /s. Determine the velocity of the second object.

Answer»

Answer:

heyyyy

We can SOLVE the GIVEN problem by using the law of conservation of momentum.

Given

Mass of one of the OBJECTS (m₁) = 100 g = 0.1 kg Mass of the other object (m₂) = 200 g = 0.2 kg Velocity of m₁ after collision (v3) = 1.67 m/s

Velocity of m₁ before collision (v₁) = 2 m/s Velocity of m2 before collision (v₂) = 1 m/s

Find out

Velocity of m2 after collision=V4

Solution

According to the law of conservation of momentum:

TOTAL momentum before collision = Total momentum after collision

Therefore, m₁v₁ + m₂V₂ = ₁V3 + m₂V4

On sustitututing the known and given values we get

2(0.1) +1(0.2) = 1.67(0.1) + v4× (0.2)

0.4 0.167 + 0.2 × V4 V4= 1.165 m/s

Answer

Hence, the velocity of the second object becomes 1.165 m/s after the collision.

i hope it helps

mark me as brainliest

please