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Two object of mass 5 kg and 8 kg at rest. F1 and F2 are the forces applied on the boat respectively. if the speed of both the object after 10 second become 10 metre per second and 20 metre per second then find the value of F1 - F2 |
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Answer» Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of MOTION, the acceleration (a) produced in the system can be calculated as:F=ma a= mF = 30600 =20m/s 2 When force F is applied on body A:The EQUATION of motion can be written as: F−T=m 1 aT=F−(m 1 )a =600−10×20=400 N (i)When force F is applied on body B: The equation of motion can be written as: F−T=m 2 a T=F−(m 2 )aT=600−20×20=200 N (ii)which is DIFFERENT from value of T in case (i). Hence our answer depends on which mass end, the force is applied. |
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