1.

two numbers differ by 2 and their product is 360 then the numbers are

Answer»

x - y = 2, x y = 360; x^2 -20x +18x - 360; x( x - 20) + 18( x - 20); ( x + 18)( x - 20);, x = -18 & 20;

let 1st no be X , 2nd no = x+3x(x+2)=360x^2+2x-360=0x^2+20x-18x-360=0x(x+20)-18(x+20)=0(x+20)(x-18)=0either x+20=0 , x = -20or x-18=0, x= 18so when x= -20 (1st no)2nd no = x+2= -20+2= -18when x=18(1st no )so 2nd no = x+2= 18+2=20so nos may be ( -20, -18) or (18,20)

the numbers are 18 and 20



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