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two number differ by 40 when each number is increased by 8, the bigger number becomes tries the lesser number if no is x, other number be 40-x ? |
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Answer» Let bigger number = x Smaller number = 40 - x If each number is increased by 8 The new numbers are , Bigger number = x + 8 Smaller number = 40 - x + 8 = 48 - x According to the problem given , x + 8 = 3 ( 48 - x ) x + 8 = 144 - 3x x + 3x = 144 - 8 4x = 136 x = 136/4 x = 34 Therefore , The bigger number = x = 34 Smaller number = 40 - x = 40 - 34 = 6 I hope this helps you. absolutely correct.... |
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