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Two non-reactive gases A and B are present in acontainer with partial pressures 200 and 180 mmof Hg. When a third non-reactive gas C is addedthen total pressure becomes 1 atm then molefraction of C will be(1) 0.75(2) 0.5(3) 0.25(4) Cannot be calculated |
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Answer» 2 non-reactive gases A & B present in a container with partial pressure 200 and 180 mm of Hg. When a third non-reactive gas C is added, then the total pressure becomes 1 ATM. What is the mole fraction of C? Answer 4 Follow Request More Ad by Worldquant University At Worldquant University, all tuition costs are covered. MSc programs in financial engineering can cost more than $50K but ours is tuition-free for every student. Apply Now 5 ANSWERS  Ameya Deshmukh, studies Science and Mathematics at St. Joseph's Convent High School, Jalgaon (2019) Answered Sep 16, 2017 According to Dalton's Law of Partial Pressures, here, the pressure exerted by C will not be affected by A and B. And the total pressure exerted will just be the scalar sum of all the partial pressures. Letxbe the partial pressure of C. Hence- 200 mm of Hg + 180 mm of Hg + x =1 atm x = 1 atm-380 mm of Hg But 1atm = 760 mm of Hg. Therefore,x = 760-380=380 mm of Hg. Moreover, Partial Pressure Mole fraction × Total Pressure Hence- 380 mm of Hg= X of A × 760 mm of Hg. X of C = 1/2 =0.5 The mole fraction of C is0.5 |
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