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two natural number are selected from first 60 natural number and are multipled. what is the probability that their product is divisible by 4 |
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Answer» ONG>Answer: Correct OPTION is C 10 1
Let the two non-negative integers selected be a and b. Then a=10α+a 1
and b=10β+b 1
, where α,β≥0 and 0 1 ,b 1 ≤9 Thus, number of possible cases for (a 1 ,b 1 ) is 10×10=100 Out of these 100, (0,0),(1,9),(2,8),(3,7),(4,6),(5,5),(6,4),(7,3),(8,2) and (9,1) are favourable. Hence, the probability of the required EVENT is 100 10 = 10 1 |
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