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Two moles of an ideal monoatomic gas are expanded according to the equation pT=constant form its initial state `(p_0, V_0)` to the final state due to which its pressure becomes half of the initial pressure. The change in internal energy is A. `(3)/(4)P_(0)V_(0)`B. `(3)/(2)P_(0)V_(0)`C. `(9)/(2)P_(0)V_(0)`D. `(5)/(2)P_(0)V_(0)` |
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Answer» `PT=`constant `P_(0)T_(i)=(P_(0))/(2)T_(i)` `rArr T_(f)=2T_(i)` Also, `P_(0)V_(0)=2R.T_(i)` `T_(i)=(P_(0)V_(0))/(2R)`….(`1`) `P_(f)V_(f)=nR.T_(f)` `rArr (P_(0))/(2)V_(f)=[2][R][2T_(f)]`…..(`2`) `rArr T_(f)=(P_(0)V_(0))/(R )` `:. DeltaU=(3)/(2)nRDeltaT=(3)/(2)P_(0)V_(0)` |
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