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Two moles of an ideal gas X occupying a volume C exerts a pressure P.The same pressure is exerted by one of another gas Y occupying a volume 2V.If the molecular weight of Y is 16 times the molecularweight of X,find the ration of the rms speeds of the molecules of X and Y. |
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Answer» SOLUTION :`V_(rms)=SQRT((3PV)/(nM))((m)/(M)=N)` `(V_(1rms))/(V_(2rms))=sqrt((V_(1))/(V_(2))(n_(2))/(n_(1))(M_(2))/(M_(1))),(V_(1rms))/(v_(2rms))=sqrt((V)/(2V)((1)/(2))(16)/(1))` `(V_(1rms))/(V_(2rms))=2` |
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