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Two moles of an ideal gas are allowed to expand from a volume of 10 `dm^(3)` to `2m^(3)` at 300 K against a pressure of 101.325 kPa. Calculate the work done.A. `-201.6` kJB. `13.22` kJC. `-810` JD. `-18.96` kJ |
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Answer» Correct Answer - A `V_(1) = 10 dm^(3) = 10p^(-2) m^(3)` `V_(2) = 2m^(3)` P=`101.325 xx 10^(3)` Pa `W= P DeltaV = -101. 325 xx 10^(3)(2-0.01)` `=-201.6` kJ |
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